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3 years ago

How do you write a letter to the editor of a newspaper in reference to bullying

Physics

1 answer:

suter [353]3 years ago

5 0

How do you write a letter to the editor?

Open the letter with a simple salutation. ...

Grab the reader's attention. ...

Explain what the letter is about at the start. ...

Explain why the issue is important. ...

Give evidence for any praise or criticism. ...

State your opinion about what should be done. ...

Keep it brief. ...

Sign the letter.

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If a magnet repels a metal object what can you say about the pole of the magnet and the pole of the object?

sleet_krkn [62]

Poles are the same D is the right answer

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How long a star lives and what it becomes at the end of its life depends primarly on what

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3 years ago

If a small number of tree frogs migrate to a mat of vegetation that is already home to an established population of tree frogs a

Bingel [31]

Answer:

Explanation:

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3 years ago

On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

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3 years ago

To the nearest tenth, what is the area of the shaded segment when JA=8ft ??

Murrr4er [49]

$A=\dfrac{1}{6}\pi 8^2-\dfrac{8^2\sqrt{3}}{4}\approx 5.8\;[ft^2]$
Answer: <span>C. 5.8 ft squared</span>

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3 years ago

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