The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.
The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.
<h3>What is a Circuit ?</h3>
In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.
- The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.
Hence, flow control circuit design that can best control an overrunning load is the opposing circuit
Learn more about Circuit here:
brainly.com/question/26064065
#SPJ4
If it takes

seconds to reach the car, then the distance

is

.
The bear's distance from the tourist's starting point is

For maximum

, we set the equations equal to each other:



so the distance is
Explanation:
Load=800N
Effort=200N
1. Mechanical Advantage = LOAD/EFFORT
= 800N/200N
= 4
2 Velocity Ratio = no. Of pulleys =5
3. Efficiency = Mechanical advantage / velocity ratio × 100%
= (4/5)×100%
=80%
4. output work= load×load distance
= 800N × 5m
= 4 × 1000J
5. Efficiency = (output work/input work) ×100%
Or, 80% = (4000J/input work) ×100%
Or, 80%/100% = 4000J/inputwork
Or, 4/5 = 4000J/inputwork
Or, input work =4000J × 5/4
Input work = 5×1000J
I hope it helped! ;-)
Answer:
v
2
=v
0
2
+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x
Explanation: