Answer:
The new force between the charges becomes double of the initial force.
Explanation:
The force acting between charge particles is given by :

k is electrostatic constant
r is distance between charges
If one of the charges are doubled, then, q₁ = 2q₁
The new force becomes,

So, the new force between the charges becomes double of the initial force.
Answer:
<em>1.228 x </em>
<em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x
N
modulus of elasticity E = 85 GN/m^2 = 85 x
Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A =
=
= 1256.8 mm^2
area of hole a =
=
= 549.85 mm^2
Total contraction of the bar =
total contraction =
==>
= <em>1.228 x </em>
<em> mm </em>
I'm not sure if a figure or some choices go along with this, but the closer to the sea floor the diver is, the lower the potential energy
Mass of the object is given as

now the speed of object is given as

here we know that


now we will have

now we will have kinetic energy of the object as



now the power is defined as rate of energy
so here we can find power as


so above is the power used for the object
Distance fallen = 1/2 ( V initial + V final ) *t
We know
a = -9.8 m/s2
t=120s
To find distance fallen, we need to find V final
Use the equation
V final = V initial + a*t
Substitute known values
V final = 0 + (-9.8)(120)
V final = -1176 m/s
Then plug known values to distance fallen equation
Distance fallen = 1/2 ( 0 + 1176 )(120)
= 1/2(1776)(120)
=106,560 m
This way plugging into distance equation is actually the long way. A faster way is to plug the values into
Distance fallen = V initial * t + 1/2(a*t)
We won't need to find V final using another equation.
But anyways, good luck!