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3 years ago

Abc is bisected by bd for what value of x will dx= day be true?

Mathematics

1 answer:

Reil [10]3 years ago

5 0

Answer:

$x=3\\$

Step-by-step explanation:

Note that because BD is an angle bisector, then angle XBD and angle DXY are equal. Also note that BYD and BXD are equal because they are both right angles. Also, by the transaitive property, BD = BD. Therefore, it can be concluded that BXD is congruent to BYD.

Therefore, we must solve $5x+4=19 \Longrightarrow 5x = 15 \Longrightarrow x=3$ .

You might be interested in

If x2=4(5-1) what is the value of x

Deffense [45]

X2=4(5-1)
x2=4(4)
x2=16
x=4

Check: 4 squared (4 times 4) equals 16. When you square a number, you multiply the number by itself.

5 0

4 years ago

Two numbers totals -14, and their difference is 6. Find the two numbers

natita [175]

Answer:

The two numbers are -4 and -10.

Step-by-step explanation:

x+y=-14

x-y=6

----------

2x=-8

x=-8/2

x=-4

-4+y=-14

y=-14-(-4)=-14+4=-10

x=-4, y=-10.

4 0

3 years ago

Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )

Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

$(\frac{a + b}{b} - \frac{a}{a + b}) \div ( \frac{a + b}{a} - \frac{b}{a + b})$

$(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})$

$\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}$

$\implies \frac{a}{b}$

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0

3 years ago

Read 2 more answers

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago

There are 550 students at Martin Middle School. One bundred and eighty- seven students walk to school. what percent of the stude

Anvisha [2.4K]

For a question like this, all you have to do is remember that a percentage is simply a fraction expressed as a decimal. So, all we have to do is:
$\frac{187}{550}$ , and then multiply our decimal answer by 100 to get the percentage:
$\frac{187}{550}$ = 0.34
0.34 x 100 = 34
Therefore 34% of the students walk to school.
I hope this helped and remember to please try and understand the maths that got the answer, not just writing the answer down :))

4 0

3 years ago