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vagabundo [1.1K]
3 years ago
10

Graph the line that passes through the points (8,0) and (2,6) and determine the

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

y= -x+ 8

Step-by-step explanation:

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A marathon is 138,336 ft long. how long is this distance in miles?
Vlad1618 [11]
It is about 26.2 miles.

1 foot = about 0.000189394
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3 years ago
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How many times would m^1/4 need to be expressed as a repeated factor in order to obtain m^2?
Marianna [84]
B.4
1/4 divided by 2 
do the reciprocal
1/4 times 1/2=2/8
divide 8by 2

3 0
3 years ago
Y=23x+5 and<br><br> y=x+3<br><br> what is the solution
kondor19780726 [428]

Answer:

I solved this like you would a system of equations - if that is not the answer you need LMK

Point form:

(- 1/11, 32/11)

Equation Form:

x = -1/11, y = 32/11

Step-by-step explanation:

8 0
3 years ago
Check
asambeis [7]

Answer:

Step-by-step explanation:

An equation contains a sign equality (=) between two expressions.

And an expression is a simple algebraic statement.

By these definitions,

          Equations                          Expressions

         x = 2x + 5                            21x - 13 + 11x

         \frac{1}{2}x=5+3                           -3.7x - 13  

         3x + 1 = -2.1                          \frac{1}{2}x+5

7 0
3 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
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