Let's look at each one of the intervals.
Interval A
Interval A looks like she's going at a pretty steady pace, so Interval A is not the correct answer.
Interval B
Interval B looks like she stays at 2.5 for an hour. That looks like a traffic jam to me!
The correct answer is Interval B.
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Answer:
w=2r
r= w/2
r- w/2 = 0
w -2r= 0
Step-by-step explanation:
Let w be the number of weeks and r be the number of recipes learnt . So he will learn 2 recipes each week .Equating gives
w=2r
when w= 1
w= 2(1) = 2
For 1st week 2 recipes are learned
when w= 2
w= 2( 2) = 4
For 2nd week 4 recipes are learned.
or
when r= 2
r= w/2
r =2/2 = 1 one recipe is learned in half of the week
r- w/2 = 0
or
w -2r= 0
Answer:
508
Step-by-step explanation:
28*16= 448
6*6= 36
4*6= 24
448+36+24= 508
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
Answer:
Step-by-step explanation:
For each name, there are only two outcomes. Either the name is authentic, or it is not. So, we can solve this problem using the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And 
is the probability of X happening.
In this problem.
5 names are selected, so 
A success is a name being non-authentic. 40% of the names are non-authentic, so 
.
We have to find 
Either the number of non-authentic names is 0, or is greater than 0. The sum of these probabilities is decimal 1. So:
So
