Answer:
ρ₀ = 3λ/(2πR⁴)
Explanation:
If we take an elemental part of the cross sectional Area of the infinitely long cylinder.
The small elemental part has a small length dr in the cylinder's radial direction such that the cross sectional Area of the elemental part = 2πr dr
The linear density over the entire radial length of the cylinder will be equal to the sum of (volume charge density × elemental cross sectional Area)
That is,
λ = Σ ρ₀rR × 2πr dr
summing from 0 to R
λ = ∫ᴿ₀ (ρ₀rR × 2πr) dr
λ = ∫ᴿ₀ ρ₀R × 2πr² dr
λ = [ρ₀R × 2πr³/3 ]ᴿ₀
λ = (2π ρ₀R/3) [ r³ ]ᴿ₀
λ = (2π ρ₀R/3) [ R³ ]
λ = 2π ρ₀R⁴/3
ρ₀ = 3λ/(2πR⁴)
Answer:
38%
Explanation:
The following data is obtained from water property tables:
Part a)
distance between sun and earth is 1 AU
now 1 light year is defined as distance covered by light in one year
so we will have
So 1 Ly is more than the distance between sun and earth
<span>Colligative
properties depend on the amount of solute dissolved in a solvent. These set of
properties do not depend on the type of species present. These properties
include freezing point depression, boiling point elevation, osmotic pressure and
vapor pressure lowering.<span> The one that would have the highest freezing point would be the sucrose (FIRST OPTION) since its vant hoff factor is 1. Hope this answers the question.</span></span>