Answer:
The torque in the coil is 4.9 × 10⁻⁵ N.m
Explanation:
T = NIABsinθ
Where;
T is the torque on the coil
N is the number of loops = 9
I is the current = 7.8 A
A is the area of the circular coil = ?
B is the Earth's magnetic field = 5.5 × 10⁻⁵ T
θ is the angle of inclination = 90 - 56 = 34°
Area of the circular coil is calculated as follows;
T = 9 × 7.8 × 0.0227 × 5.5×10⁻⁵ × sin34°
T = 4.9 × 10⁻⁵ N.m
Therefore, the torque in the coil is 4.9 × 10⁻⁵ N.m
Answer:
a) 4.98m/s²
b) 481.66N
Explanation:
a) Using the Newtons second law of motion
m is the mass of the object
g is the acceleration due to gravity
Fm is the moving force acting along the plane
Ff is the frictional force opposing the moving froce
a is the acceleration of the skier
Given
m = 60kg
g = 9.8m/s²
= 35°
Ff = 38.5N
Required
acceleration of the skier a
Substituting into the formula;
Hence the acceleration of the skier is 4.98m/s²
b) The normal force on the skier is expressed as;
N = Wcosθ
N = mgcosθ
N = 60(9.8)cos 35°
N = 588cos 35°
N = 481.66N
Hence the normal force on the skier is 481.66N
Answer:
The displacement, the time and the direction
Explanation:
The velocity of an object is defined as:
where
d is the displacement, which is a vector describing the change in position of the object
t is the time in which the displacement takes place
Since d (the displacement) is a vector, velocity is a vector as well: this means that it also has a direction, which corresponds to the direction of the displacement.
The magnitude of the velocity, insteand, is called speed.
Answer:
Given: velocity from ( vovo ) 10 m/s to ( vfvf ) 15 m/s after traveling(d) 5 meters.
Use of this equation:
v2f=v2o−2⋅a⋅dvf2=vo2−2⋅a⋅d
152=102+2⋅a⋅5152=102+2⋅a⋅5
225 = 100 + 10a
125 = 10a
a = 12.5 m/s 22
Answer:
B) 18.5 m/
s west
Explanation:
Scalar quantity has MAGNITUDE only
Vector quantity has MAGNITUDE and DIRECTION
Hope this is correct and helpful
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