All categories

3 years ago

If a 60-g object has a volume of 30 cm", what is its density?

Physics

1 answer:

alisha [4.7K]3 years ago

5 0

Answer:

Density = Mass/volume. D= 60/30.Divide it and you'll get ur answer as 2

You might be interested in

Find the acceleration a body whose velocity increases from 11m/s to 33m/s in 10 seconds

solong [7]

Answer:

1.1 m/(s)^2

Explanation:

u=11 m/s

v=33 m/s

t=10s

v=u+at

=> 33=22+(a)(10)

=> 33-22=10a

=> 10a=11

=> a=11/10=1.1 m/(s)^2

7 0

2 years ago

When a piece of metal mass of 72.17 g is

nordsb [41]

Answer:

Explanation:

The trick is in finding the volume.

Final Volume = 26.64

Initial Volume=<u>20.92</u> Subtract

Metal Volume 5.72 cm^3

Density = mass / volume

Density = 72.17 / 5.72

Density = 12.617

7 0

2 years ago

Name 5 machine principles

lidiya [134]

The Wheel & Axle. The wheel has always been considered a major invention in the history of mankind

The Inclined Plane

The Wedge

The Pulley

The Screw

3 0

3 years ago

A mountain climber starts at the base of a mountain, climbs all the way to the

loris [4]

Answer:

the answer is d

Explanation:

you get exhausted at the middle because it is steep.

3 0

2 years ago

Read 2 more answers

A particle moves at a constant speed in a circular path with a radius of r=2.06 cm. If the particle makes four revolutions each

nataly862011 [7]

The centripetal acceleration is $13.0 m/s^2$

Explanation:

For an object in uniform circular motion, the centripetal acceleration is given by

$a=\frac{v^2}{r}$

where

v is the speed of the object

r is the radius of the circle

The speed of the object is equal to the ratio between the length of the circumference ( $2\pi r$ ) and the period of revolution (T), so it can be rewritten as

$v=\frac{2\pi r}{T}$

Therefore we can rewrite the acceleration as

$a=\frac{4\pi^2 r}{T^2}$

For the particle in this problem,

r = 2.06 cm = 0.0206 m

While it makes 4 revolutions each second, so the period is

$T=\frac{1}{4}s = 0.25 s$

Substituting into the equation, we find the acceleration:

$a=\frac{4\pi^2 (0.0206)}{0.25^2}=13.0 m/s^2$

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0

3 years ago