KE= (1/2) mv²
So, the variables we need to include in our question would be a varable for a mass(m) of an object at some velocity(v).
My Answer:
(This is just an example question, yours can be different)
What is the Kinetic Energy experienced by an bouncy ball rolling at 7m/s (that's your velocity) across a frictionless surface that has a mass(m) of 10 grams?
Answer:
The amplitude of the subsequent oscillations is 13.3 cm
Explanation:
Given;
mass of the block, m = 1.25 kg
spring constant, k = 17 N/m
speed of the block, v = 49 cm/s = 0.49 m/s
To determine the amplitude of the oscillation.
Apply the principle of conservation of energy;
maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

Therefore, the amplitude of the subsequent oscillations is 13.3 cm
Answer:
E = 3.049 N/C
Explanation:
Induced electric field = e/2 *(pi) *r
Induced electric field = e /(3.14 *19.5) - Eq (1)
e = (pi)r^2*B/t
= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1
= 1.867 V
Substituting this value in equation 1, we get –
E = 1.867 V/(3.14 *19.5/100)
E = 3.049 N/C
The strong nuclear force isnt quite strong enough to overcome electrosatic repulsion between two protons