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Andreas93 [3]
3 years ago
5

Difference Between Newton's first law and third law of motion​

Physics
2 answers:
Lena [83]3 years ago
3 0

Newton first law state that anything in motion or rest will remain in motion or in rest until an external force is applied

Newton third law of motion state that every action have equal and opposite reaction

Oksi-84 [34.3K]3 years ago
3 0

Answer:

Newton's laws of motion relate an object's motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. ... In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

mark me brain list please

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Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
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Answer:

Fnet = 12 N

Explanation:

Force on a point charge due to another point charge = kq1q2 / d^2

Force on +32uC = due to + 20uC + due to -60uC

where uC = 1 x 10^-6 C and k = 9 x 10^9 N m^2 / C^2

Net Force =

= \frac{1}{4\pi \epsilon _0} [\frac{32 \times 10^-^6 \times60\times10^-^6}{(60/100)^2}-\frac{32 \times 10^-^6 \times20\times10^-^6}{ (40/100)^2}  ]

F_{net}=9 \times10^9\times 10^-^1^2[\frac{32\times60\times10^4}{60\times60} -\frac{32\times20\times10^4}{40\times40} ]

=90[32(\frac{80-60}{60\times 80} )]\\\\=90\times32\times0.004167\\\\=12N

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Explanation: Hope this helps!

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a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dea
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<u>The number of variations the dealership have is 40 cars</u>.

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This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

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Answer with explanation:

Part a)

v_{radial}=\frac{dr}{dt}=\frac{d(2+0.7t^{2})}{dt}\\\\v_{radial}=1.4t\\\\\therefore v_{radial}|_{t=4}=1.4\times 4=5.6ft/s\\\\v_{angular}=r|_{t=4}\times \frac{d\theta }{dt}=13.2\frac{3.5t}{dt}=46.2fts^{-1}\\\\\therefore v=\sqrt{v_{radial}^{2}+v_{angular}^{2}}\\\\v=46.53ft/s

Part b)

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