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Andreas93 [3]
3 years ago
5

Difference Between Newton's first law and third law of motion​

Physics
2 answers:
Lena [83]3 years ago
3 0

Newton first law state that anything in motion or rest will remain in motion or in rest until an external force is applied

Newton third law of motion state that every action have equal and opposite reaction

Oksi-84 [34.3K]3 years ago
3 0

Answer:

Newton's laws of motion relate an object's motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. ... In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

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What type of objects exert gravitational pull? (5 points) Only living objects Only space objects All objects having mass All sub
Yanka [14]

Answer:

Every object in the universe that has mass exerts a gravitational pull, or force, on every other mass. The size of the pull depends on the masses of the objects. You exert a gravitational force on the people around you, but that force isn't very strong, since people aren't very massive.

6 0
3 years ago
Estimate how fast your hair grows, in units of m/s, assuming it takes 30 days for your hair to grow 1 inch. note that 1 inch =2.
dedylja [7]

Answer:

1) 9.8×10⁻⁹ m/s

2) 50970.3238656 L

Explanation:

1) In 30 days hair grows 1 inch

1 inch = 2.54 cm

1 cm = 0.01 m

2.54 cm = 2.54 × 0.01 m

⇒2.54 cm = 0.0254 m

30 days = 30×24×60×60 = 2592000 seconds

Speed = Distance / Time

\text{Speed}=\frac{0.0254}{2592000}=9.8\times 10^{-9}\ m/s

Speed at which hair grows is 9.8×10⁻⁹ m/s

2) 1 ft = 0.3048 m

0.3048 m = 30.48 cm

1 ft = 30.48 cm

15 ft = 15×30.48 = 457.2 cm

8 ft = 8×30.48 = 243.84 cm

Volume of water in pool = Length × Width × Depth

⇒Volume of water in pool = 457.2×457.2×243.84

⇒Volume of water in pool = 50970323.8656 cm³

or

Volume of water in pool = 15×15×8 = 1800 ft³

1 ft³ = 30.48³ cm³

1800 ft³ = 30.48³ × 1800 = 50970323.8656 cm³

Converting to liters

1 L = 1000 cm³

0.001 L = 1 cm³

50970323.8656 cm³ = 50970323.8656×0.001 = 50970.3238656 L

Volume of water in pool is 50970.3238656 L

6 0
3 years ago
What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?
VikaD [51]

Answer : a=10\ m/s^2

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

F = m\times a

a is the acceleration of the engine.

a=\dfrac{F}{m}

a=\dfrac{300\ N}{30\ Kg}

a=10\ m/s^2

So, the acceleration of the engine is 10\ m/s^2.

Hence, this is the required solution.

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