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frez [133]
3 years ago
13

Camels can run faster than horses in desert.Why

Physics
2 answers:
kobusy [5.1K]3 years ago
8 0
Because camels have thick and wide feet so they don't fall in the desert, also protect them from the heat of the desert
grigory [225]3 years ago
4 0

Most camels can outrun most horses, but the fastest racehorse would probably outrun the fastest camel (it would be a close race). But camels can carry more weight and can move at average speeds of about 12 kilometer per hour for as much as 18 hours.

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An olympic hurdler accelerates at a rate of 15.5 m/s2 . what is the rate in miles/min2 ?
Wittaler [7]
You have to use conversion units for this. For every 1 mile, there is an equivalent amount of 1,609 meters. For every 1 minute, there is an equivalent amount of 60 seconds. Using the dimensional analysis approach, the solution is as follows:

Acceleration = 15.5 m/s²*(1 mile/1,609 m)*(60 s/1 min)² = 34.68 miles/min²
5 0
3 years ago
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What does the term equilibrium refer to
igor_vitrenko [27]
Equilibrium<span>-the condition of a system when no observable change is taken place or the kinetic energy is equal. </span>Equilibrium means<span> to stay balanced or equal.</span>
6 0
3 years ago
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A particular baseball pitcher throws a baseball at a speed of 39.1 m/s (about 87.5 mi/hr) toward home plate. We use g = 9.8 m/s2
Reika [66]
There is no acceleration in the horizontal direction (just g in the vertical), so we can use v = d/t, where v is velocity, d is distance and t is time. We can solve for time like so: t = d/v, we can plug in numbers (v is 39.1m/s completely in the horizontal direction, so no need to break it down with sin's and cos's, just plug it in) and we get t = (16.6m)/(39.1 m/s) = 0.42 s. Keep in mind it wouldn't fall far enough vertically to hit home plate (though we don't know the ball's initial height anyway), but would be in the air just above it. Cheers!
6 0
3 years ago
What an object is placed 8 mm from a concave spherical mirror a clear image can be projected on the screen 16 mm in front of me
alexgriva [62]

Concept: The magnification of spherical mirror can be defined by two ways.

(i) In terms of the height of the object and image.

The magnification of the spherical mirror is defined as the ratio of the height of the image'h_{i}' to the height of the object 'h_{o}'. It is denoted by letter 'm'.

Mathematically, it can be written as

m= \frac{h_{i}}{h_{o}}   ------------(1)

(ii) In terms of the object's and image's distances.

The magnification of the spherical mirror is defined as the negative ratio of the image distance'd_{i}' to the object distance 'd_{o}'.

Mathematically, it can be written as

m= - \frac{d_{i}}{d_{o}}   ------------(2)

Now, from equation (1) and (2) we have,

m = \frac{h_{i}}{h_{o}}   = -  \frac{d_{i}}{d_{o}}  -----------(3)

Given: Spherical Concave Mirror,

We will consider positive sign for object's and image's distance because both are in front of the mirror.

Object distance (d_{o}) = + 8 mm.

Image distance (d_{i}) = + 16 mm

Object's height (h_{o}) = + 4 mm

Image's height (h_{i}) =?

Now, apply equation (3)

\frac{h_{i}}{h_{o}}   = - \frac{d_{i}}{d_{o}}

Or,   \frac{h_{i}}{4 mm}   = - \frac{+16 mm}{+8 mm}

Or, hi = - 8 mm

Here; negative sign means, the image will be inverted.

The image's height will be 8 mm.

4 0
3 years ago
PLS ANSWER FAST WILL GIVE BRAINLEST!!!!
amid [387]

Answer:

F = 500 N

Explanation:

F = m × a

F = 1,000 × 0.5

F = 500 kg m/s²

F = 500 N

7 0
3 years ago
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