Answer:
Explanation:
- given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s
- acceleration = 0.032 X 2 /(1.30×10−8)^2
a = 3.79 x 10^14m/s^2
E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19
E = magnitude of this electric field. = 2156.3N/C
b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as
= 2 X 3.79 x 10^14 X 0.032
= 4.92 X 10^6m/s
A wave with a large amplitude
a wave check
Answer:
520 miles per hour
Explanation:
Let the speed of the Boeing 747 be x miles per hour.
The small airplane covers distance of 780 miles with speed 260 miles per hour.
Also,
After 1.5 hours the Boeing 747 leave the same place and reaches at same time. Both covered distance of 780 miles.
So,
<u>Time taken by Boeing 747 + 1.5 hours = Time taken by small plane.</u>
Also,
Time = Distance/ speed
So,
780 / x + 1.5 = 780/ 260
Solving for x, we get:
<u>x = 520 miles per hour</u>
