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Luda [366]
3 years ago
6

A uniform meter stick (with a length of 1.00 meter) has a mass of 108 g. It is supported at its midpoint by a vertical rigid blu

e rod (the two are connected by a frictionless hinge). A weight (mass 1) has a mass of 21g and it hangs from a (massless) string at a distance of 24 cm from the left end of the stick. Another weight (mass 2) has a mass of 27 g and it hangs from a string at a distance of 91 cm from the left end of the stick. The system was held motionless by the (vertical) blue rod and by a vertical red string at the right end of the stick (one meter from the left end of the stick). Red string Then somebody cut the red string. The blue rod still holds the center of the stick in place but the system can now rotate about the midpoint of the stick Immediately after the red string is cut.
Find the vertical tension in the blue rod.
1. 508 N
2. 143 N
3.153 N
4. 0.4704N
5. 0.7644N
6. 1.539 N

Physics
1 answer:
alexandr1967 [171]3 years ago
4 0

Answer:4

Explanation:

Given

m_1=21\ gm

m_2=27\ gm

Mass of stick is m=108\ gm

Let T be the tension in the red string

Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut

Therefore

T=m_1g+m_2g

T=(0.021+0.027)\times 10

T=0.48\ N

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3 years ago
A box falls off of a tailgate and slides along the street for a distance of 62.5 m. Friction slows the box at –5.0 m/s2. At what
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Answer:

25 m/s

Explanation:

This question can be solved using equation of motion

v^2 = u^2 + 2as

where

v is the final velocity

u is the initial velocity

s is the distance covered while moving from initial to final velocity

a is the acceleration

_____________________________________________

Given

box moved for distance of 62.5 m

Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.

thus in this problem

a = -5.0 m/s2

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u the initial velocity we have to find

the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.

so if we find speed of box, we will be able get sped of truck as well.

using equation of motion

v^2 = u^2 + 2as\\0^2 = u^2 + 2*-5* 62.5\\0 = u^2 - 625\\u^2 = 625\\\sqrt{u^2} = \sqrt{625} \\u = 25

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3 0
3 years ago
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ASHA 777 [7]

Answer:

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make e the subject of the equation

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e = √(0.000125)

e = 0.011 m.

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