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MAVERICK [17]
3 years ago
9

Can someone plz answere my question for science

Physics
1 answer:
klio [65]3 years ago
5 0
Whats the question?
djdkkd
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The first mechanized industry was
Oxana [17]
C. Textiles

It was the first thing mechanized in the Industrial Revolution

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3 years ago
What is the latent power in the source ​
levacccp [35]

Answer:What?

Explanation:

4 0
3 years ago
A compressed gas cylinder containing 1.50 mol methane has a volume of 3.30 L. What pressure does the methane exert on the walls
sweet-ann [11.9K]

Answer:

P=11.126 atm

Explanation:

We are given that a compressed gas cylinder containing 1.50 mol methane

Volume of methane in a gas cylinder =3.3 L

Temperature =25^{\circ}=25+273.15=298.15 K

We have to find the pressure exert by gas on cylinder

Using ideal gas equation

PV =nRT

Where R= gas constant=0.0821 L-atm/K mol

Substitute all given values

Then we get

P\times 3.3=1.5\times 0.0821\times 298.15

P=\frac{36.717}{3.3}

P=11.126 atm

Hence, the pressure exert by the gas on cylinder =11.126 atm

4 0
4 years ago
Read 2 more answers
Satellite C revolves around Earth 10 times a day. What is the radius of its orbit, measured from Earth's center? Assume that Ear
frez [133]

The radius of its orbit, measured from Earth's center, will be 1.44 × 10⁷ mm.

<h3>What is Newton's law of gravitation?</h3>

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Given data in problem is;

The mass of Earth is, \rm m_E = 5.98 \times 10^{24} \ kg

Gravitational constant, G =6.674 × 10⁻¹¹ N m₂/kg²

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

\rm F_g = \frac{Gm_sm_e}{r^2}

The centripetal force due to rotation of the satellite;

\rm F_c = \frac{m_s v^2}{r}

The centripetal and the gravitational force are equal;

\rm F_g = F_c  \\\\  \frac{Gm_sm_e}{r^2} =  \frac{m_s v^2}{r} \\\\ r = G \frac{m_E }{v^2 } \\\\ r = G \frac{m_E }{(r \omega )^2 } \\\\ r = \sqrt[3]{\frac{Gm_E}{\omega^2}} \\\\ r = \sqrt[3]{\frac{6.67 \times 10^{-11}(5.98 \times 10^{24})}{(3.63 \times 10^{-4})^2}} \\\\ r = 1.44 \times 10^7   \ mm

Hence, the radius of its orbit measured from Earth's center will be 1.44 × 10⁷ mm.

To learn more about Newton's law of gravitation, refer to the link.

brainly.com/question/9699135.

#SPJ1

8 0
2 years ago
A stone is thrown straight up from the roof of an 80 ft building. the height, in feet, of the stone at any time t, in seconds, m
julsineya [31]

Answer:

144 ft

Explanation:

h(t) = -16t² + 64t + 80

The maximum height is at the vertex.  We can find the vertex of a parabola using -b / (2a):

t = -64 / (2×-16)

t = 2

The vertex is at 2 seconds.  The height of the stone at this time is:

h(2) = -16(2)² + 64(2) + 80

h(2) = 144

The maximum height is 144 feet.

8 0
4 years ago
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