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ss7ja [257]
3 years ago
7

To solve the equation: 14 = t +72 This is a(n)

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

t=-58

Step-by-step explanation:

14=t+72\\14-72=t+72-72\\-58=t

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Vanna is saving for a trip. The hotel room will be $298.17 for 3 nights, and there will be additional fees. What is her daily co
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The daily cost is $99.39.

Step-by-step explanation:

In order to find the answer with the information provided, you have to divide the price given for 3 nights by the number of nights to determine the price per night which would be her daily cost:

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6 0
3 years ago
Fred buys a binder for $4.50 and six reams of paper. Latasha buys an ink cartridge for $17.50 and four reams of paper. Both spen
kondor19780726 [428]

Answer:

The the price of one ream of paper is $6.5.

Step-by-step explanation:

Here, Let us assume the cost of one ream of paper  = $  m

<u>The money spent by Fred:</u>

The money spent on a  binder  = $4.50

The money spent on 6 ream of papers  =  6 x ( cost of 1 ream )

= 6 x ($m) = 6 m

⇒The total money Fred spent  = Money spent on (binder + 6 ream of papers)  

= 4.50 + 6 m  ....... (1)

<u>The money spent by Latasha:</u>

The money spent on a cartridge = $17.50

The money spent on 4 ream of papers  =  4 x ( cost of 1 ream )

= 4 x ($m) = 4 m

⇒The total money Latasha spent  = Money spent on (cartridge + 4 ream of papers)  

= 17 .50 + 4 m  .... (2)

Also, Both spend the same amount of money

⇒4.50 + 6 m = 17 .50 + 4 m   ( from (1) and (2))

or, 6 m - 4  m= 17. 50 - 4, 50

or, 2 m =  13

or, m = 13/ 2  = 6.5

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Hence, the the price of one ream of paper is $6.5.

7 0
3 years ago
If
Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

6 0
2 years ago
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