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mafiozo [28]
3 years ago
13

Write an equation for a line parallel to y=2x-2 and passing through the point (1,1) Y=???? PLEASE HELP ANYONE

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
The general equation for slope-intercept form is y = mx + b, where m = the slope of the equation, b = the y intercept, and x and y are your variables (and the coordinate points on the graph). 

Remember that for parallel lines, the slope, m, is the same for both equations. The equation you're given, y = 2x - 2, is already in slope-intercept form and the 2 in front of x is m, your slope. That means for whatever equation we come up with, m has to be 2. 

So far we know the equation for our parallel line is y = 2x + b. How do we figure out b? Plug in the (x, y) coordinate you're given, (1, 1) and solve for b:
y = 2x + b\\
1 = 2(1) + b\\
1 = 2 + b\\
b = -1

Now we know b = -1. Put that into our y = 2x + b equation to get the final equation of your parallel line: 
Your final answer is y = 2x - 1.

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There are an infinite number of ways to do this.

Perhaps the simplest is to do it in decimal.

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Any negative decimal number between these values will do. For example, ...

  -0.67, -0.68, -0.69, -0.70, -0.71

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If you want to choose fractions that are evenly spaced between the given values, you can find their difference, then divide that difference into 6 parts (1 more than the number of numbers you need).

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_____

<em>Additional comment</em>

The fractions we came up with could be referred to as "5 arithmetic means between -2/3 and -4/5." There is nothing in the problem statement suggesting the values need to be evenly spaced.

When doing this in decimal, you can obtain a new value simply by adding more digits to the decimal fraction:

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