6 is
6/16, 9/16, 12/16, 15/16
8 is
16/18, 15/18, 14/18, 13/18
I hope this helps! If you want I can elaborate :)
The percentages for each acid are:
- 0% acid ⇒ percentage disolved = 0%
- 33% acid ⇒ percentage disolved = 1%
- 66% acid ⇒ percentage disolved = 2%
- 100% acid ⇒ percentage disolved = 4.2%
<h3>
How to get the percentages?</h3>
Here we just need to use the given formula:
![percent\ disolved = \frac{initial\ mass - \ final \ mass}{initial \ mass}*100 \%](https://tex.z-dn.net/?f=percent%5C%20disolved%20%3D%20%5Cfrac%7Binitial%5C%20mass%20-%20%5C%20final%20%5C%20mass%7D%7Binitial%20%5C%20mass%7D%2A100%20%5C%25)
For the 0% acid, the initial and final mass are the same:
initial mass = final mass = 10.3g
Then the percent dissolved is:
![percent\ disolved = \frac{10.3g - 10.3g}{10.3g}*100 \% = 0 \%](https://tex.z-dn.net/?f=percent%5C%20disolved%20%3D%20%5Cfrac%7B10.3g%20-%2010.3g%7D%7B10.3g%7D%2A100%20%5C%25%20%3D%200%20%5C%25)
For the 33% acid we have:
- initial mass = 10.1g
- final mass = 10g
Then:
![percent\ disolved = \frac{10.1g - 10g}{10.1g}*100 \% = 1 \%](https://tex.z-dn.net/?f=percent%5C%20disolved%20%3D%20%5Cfrac%7B10.1g%20-%2010g%7D%7B10.1g%7D%2A100%20%5C%25%20%3D%201%20%5C%25)
For the 66% acid:
- initial mass = 10g
- final mass = 9.8g
![percent\ disolved = \frac{10g - 9.8g}{10g}*100 \% = 2 \%](https://tex.z-dn.net/?f=percent%5C%20disolved%20%3D%20%5Cfrac%7B10g%20-%209.8g%7D%7B10g%7D%2A100%20%5C%25%20%3D%202%20%5C%25)
for the 100% acid:
- initial mass = 9.9g
- final mass = 9.5g
![percent\ disolved = \frac{9.9g - 9.5g}{9.9g}*100 \% = 4.2 \%](https://tex.z-dn.net/?f=percent%5C%20disolved%20%3D%20%5Cfrac%7B9.9g%20-%209.5g%7D%7B9.9g%7D%2A100%20%5C%25%20%3D%204.2%20%5C%25)
If you want to learn more about percentages:
brainly.com/question/843074
#SPJ1
65.9 because the hundreds placr rounds up since it is above 5
Answer:
58.3% to the nearest tenth.
Step-by-step explanation:
The prime numbers from 1 to 6 are 2,3 and 5.
The probability of a prime number taken from the result of the 300 throws:
= (sum of the frequencies for 2, 3 and 5) / ( total throws)
= (60 + 55 + 60) / 300
= 0.5833 or 58.3%.
The probability of one head must be 3/8. I believe there is a 50% chance of getting a toss of more then 1 head in 3 tosses.