Our brains judge the speed of objects passing by us through the time taken for them to cross our field of view. Those taking a long time could either be nearby and travelling slowly or faster and further away. And in the case of planes, our brains know that the second interpretation is the right one.
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
Answer is C: Step 3, because a number has been added only to one side of the equation.
Hope this helps.
0 0 0
2 3 1
4 6 2
6 9 3
the lines should be straight tho
Answer:
Step-by-step explanation:
Whenever one of the equations gives an expression for one of the variables, it is useful to use that expression to substitute into the other equation.
Using the expression for y and substituting into the second equation, we have ...
3x -5(2 +1/4x) = -3
3x -10 -5/4x = -3 . . . . . . eliminate parentheses
7/4x = 7 . . . . . . . . . . . . . add 10, collect terms
x = 4 . . . . . . . . . . . . . . . . .multiply by 4/7
y = 2 + (1/4)(4) = 3
The solution is (x, y) = (4, 3).
