Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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3.4 - 2/3 > x
2) simplify 3.4 - 2/3 to 8.2/3
8.2/3 > x
3) Simplify 8.2/3 to 2.733333.
2.733333 > x
switch sides
Answer:
x > 3
Step-by-step explanation:
2x+9<4x+3
or, 9-3<4x-2x
or, 6<2x
or, (6/2)<x
or, 3<x
or, x >3
9/16.
There is no common factor to 9 and 16.
No number can go into 9 and at the same time go into 16.
So in simplest form it is still = 9/16