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DanielleElmas [232]
3 years ago
8

Cuanto le falta a 5800 para llegar a 9000.Porfa ayuda es hasta las 6:00 porfaaaaaaaaaa

Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0
The answer would be 3200
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An agency is studying the income of store managers in the retail industry. A random sample of 25 managers reveals a sample mean
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Answer:

The Confidence Interval = ($44,745.55 , $46,094.45)

Step-by-step explanation:

The formula for Confidence Interval =

Confidence Interval = Mean ± z × Standard deviation/√n

Where n = number of samples = 25 managers

Standard deviation = $2,050

Mean = $45,420

z = z score of the given confidence interval

= z score of 90% confidence interval

= 1.645

Confidence Interval = $45,420 ± 1.645 × $2,050/√25

= $45,420 ± 1.645 × $2,050/5

= $45,420 ± 674.45

Confidence Interval =

$45,420 - 674.45 = $44,745.55

$45,420 + 674.45 = $46,094.45

Therefore, the Confidence Interval = ($44,745.55 , $46,094.45)

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3 years ago
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