All categories

3 years ago

State if each triangle is a right triangle.

Mathematics

1 answer:

Kitty [74]3 years ago

3 0

Answer:

No, It is not a right triangle

Step-by-step explanation:

For it to be a right triangle, the hypotenuse would be equal to the sum of the legs when squared.

Use the pythagorean theorem-

8^2+12^2=15^2

64+144=225

208=225

Since they aren't equal, it is not a right triangle.

You might be interested in

1. Find the measures of the following to the nearest tenth of a degree.

Dvinal [7]

B cause you take y times it by the circumference

4 0

3 years ago

Certain circle can be represented by the following equation.

kirill115 [55]

Answer:

Center of the circle is (-9, -7)

Radius of the circle = 5 units

Step-by-step explanation:

Given question is incomplete: here is the complete question.

Certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0.

What is the center of this circle ?

What is the radius of this circle ?

Since equation of the circle has been given by the equation,

x² + y² + 18x + 14y + 105 = 0

Now we will convert this equation to the standard form of the circle.

x² + 18x + y² + 14y = -105

[x² + 2(9)x] + [y² + 2(7)x] = -105

[x² + 2(9)x + 9²] + [y² + 2(7)y + 7²] = 9² + 7² - 105

(x + 9)² + (y + 7)² = 81 + 49 - 105

(x + 9)² + (y + 7)² = 25

(x + 9)² + (y + 7)² = 5²

By comparing this equation with the standard equation of the circle → (x - h)² + (y - k)² = r²

Center of the circle is (-9, -7) and radius of the circle is 5 units.

8 0

3 years ago

Read 2 more answers

Many people use scanners to read documents and store them into pdf file. To help determine which brand of scanner to buy, a stud

konstantin123 [22]

The data is missing in the question. The data is provided below :

Document : 1 2 3 4 5 6 7 8

Brand A 17 29 18 14 21 25 22 29

Brand B 21 38 15 19 22 30 31 37

Solution :

State of the hypothesis of the null hypothesis and alternate hypothesis.

Null hypothesis : $h_A = h_B$

Alternate hypothesis : $h_A > h_B$

These hypothesis is a one tailed test. The null hypothesis will get rejected when the mean difference between the sample means is very small.

Significance level = 0.05

Therefore the standard error is : $SE = \sqrt{(\frac{s^2_1}{n_1})+(\frac{s^2_2}{n_2})}$

= 3.602

And the degree of freedom, DF = 14

$t=\frac{(x_1-x_2)-d}{SE}$

= -1.319

Here, $s_1$ = standard deviation of the sample 1

$s_2$ = standard deviation of the sample 2

$n_1$ = size of the sample 1

$n_2$ = size of the sample 2

$x_1$ = mean of the sample 1

$x_2$ = mean of the sample 2

d = the hypothesis difference between the population mean

The observed difference in a sample means t static of -1.32. From t distribution calculator to determine P( $t \leq -1.32$ ) = 0.1042

Since the P value of 0.1042 is greater than significance level o 0.05, we therefore cannot reject the null hypothesis.

But from the test, we have no sufficient evidence that supports that Brand A is better than Brand B.

8 0

3 years ago

In Jaden’s yard, there is a triangular garden patch. He wants to plant a geranium in the patch at a point equidistant from all i

Lelu [443]

Answer:

Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.

Step-by-step explanation:

In Jaden’s yard, there is a triangular garden patch. He wants to plant a geranium in the patch at a point equidistant from all its vertices.

" The CIRCUMCENTER (C) of a triangle is the point in the plane equidistant from the three vertices of the triangle "

Hence Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.

5 0

3 years ago

Read 2 more answers

Find the value of cos 28°cos 62°– sin 28°sin 62°

Romashka [77]

<h2>Answer:</h2>

cos 28°cos 62°– sin 28°sin 62° = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

cos(A+B) = cosAcosB - sinAsinB -----------------(i)

We can apply such identity to solve the given expression.

Given:

cos 28°cos 62°– sin 28°sin 62°

Comparing the given expression with the right hand side of equation (i), we see that;

A = 28°

B = 62°

∴ Substitute these values into equation (i) to have;

⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°

Solve the left hand side.

⇒ cos(90°) = cos28°cos62° - sin28°sin62°

⇒ 0 = cos28°cos62° - sin28°sin62° (since cos 90° = 0)

Therefore,

cos28°cos62° - sin28°sin62° = 0

8 0

3 years ago