Answer:
388.5yd²
Step-by-step explanation:
We have Triangle TUV
In the question, we are given already
Angle U = 32°
Angle T = 38°
Angle V = ???
Side t = 31yd
Side u = ?
Side v = ?
Area of the triangle= ?
Step 1
We find the third angle = Angle V
Sum of angles in a triangle = 180°
Third angle = Angle V = 180° - (32 + 38)°
= 180° - 70°
Angle V = 110°
Step 2
Find the sides u and v
We find these sides using the sine rule
Sine rule or Rule of Sines =
a/ sin A = b/ Sin B
Hence for triangle TUV
t/ sin T = u/ sin U = v/ sin V
We have the following values
Angle T = 38°
Angle U = 32°
Angle V = 110°
We are given side t = 31y
Finding side u
u/ sin U= t/ sin T
u/sin 32 = 31/sin 38
Cross Multiply
sin 32 × 31 = u × sin 38
u = sin 32 × 31/sin 38
u = 26.68268yd
u = 26.68yd
Finding side x
v / sin V= t/ sin T
v/ sin 110 = 31/sin 38
Cross Multiply
sin 110 × 31 = v × sin 38
v = sin 110 × 31/sin 38
v = 47.31573yd
v = 47.32yd
To find the area of triangle TUV
We use heron formula
= √s(s - t) (s - u) (s - v)
Where S = t + u + v/ 2
s = (31 + 26.68 + 47.32)/2
s = 52.5
Area of the triangle = √52.5× (52.5 - 31) × (52.5 - 26.68 ) × (52.5 - 47.32)
Area of the triangle = √150967.6032
Area of the triangle = 388.5454973359yd²
Approximately to the nearest tenth =388.5yd²
Answer:
12
Step-by-step explanation:
No, in problem 1
you said that area of triangle=bh when it should be 1/2bh
the area should be 9 not 18 so triange=9
aera of rectangle is correct
so
27+9=36 in^2 is answer
2. it is 1 rectangle 1 triangle 1 square you forgot the square
rectangle=12 times 4=48
square=4 times 4=16
triangle=1/2bh=1/2(8)4=16
add
48+16+16=80 in^2
remember that
triangle=1/2(base times height)
draw immaginary lines and split shapes, it could help to seperate shapes or/and mmove them around and regroup them
Answer: the answer is A. which is 10x-2
Step-by-step explanation:
Answer:
<h3>
There is one unique real number solution at (–1, –3)</h3>
Step-by-step explanation:
Given the two linear equation
–4x – 7 = y ...1
x² – 2x – 6 = y ...2
Equating the left hand side of both equations since they are equal to the same variable y will give;
Substituting x=1 into equation 1 we have;
This means there is only one unique real number solution at (-1, -3)
