What shape cannot be a rectangle

15 less than a number tripled is equivalent to the difference of the same number and 12

Nitella [24]

Step-by-step explanation:

x = number

3x - 15 = (x - 12)×-4 or (12-x)×-4

3x - 15 = -4x + 48 or -48 + 4x

7x = 63, x = 9 or

33 = x

4 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

Solve The Following Question:<br><br> 5/13t = -9

BabaBlast [244]

5/13t= -9
Then t =( -9*13) / 5
T=-23.4

3 0

3 years ago

Read 2 more answers

Find the distance between points (5,1) and (3,4) to the nearest tenth

Charra [1.4K]

Answer:

3.6 units (nearest tenth)

Step-by-step explanation:

distance formula

= $\sqrt{(x1 - x2)^{2} + (y1 - y2)^{2} }$

Thus, distance between the 2 points

= √[(5 - 3)² + (1 - 4)²]

= √[ 2²+ ( - 3)²]

= √13

= 3.6 units (nearest tenth)

5 0

3 years ago

3c/4 - 2c/4 = 4 (solve with work please)

xxMikexx [17]

Simplifying

2c + 3 = 3c + -4

Reorder the terms:

3 + 2c = 3c + -4

Reorder the terms:

3 + 2c = -4 + 3c

Solving

3 + 2c = -4 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.

3 + 2c + -3c = -4 + 3c + -3c

Combine like terms: 2c + -3c = -1c

3 + -1c = -4 + 3c + -3c

Combine like terms: 3c + -3c = 0

3 + -1c = -4 + 0

3 + -1c = -4

Add '-3' to each side of the equation.

3 + -3 + -1c = -4 + -3

Combine like terms: 3 + -3 = 0

0 + -1c = -4 + -3

-1c = -4 + -3

Combine like terms: -4 + -3 = -7

-1c = -7

Divide each side by '-1'.

c = 7

Simplifying

c = 7

3 0

4 years ago