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Jobisdone [24]
3 years ago
11

The grocery store sells 4 cans of soup for $3.60.

Mathematics
2 answers:
LenKa [72]3 years ago
8 0
90 cents, 3.60/4 and you get the right answer
Aloiza [94]3 years ago
6 0
90 cents
3.60 divided by 4
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I WILL ABSOLUTELY GIVE YOU A BARNLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!! What is the surface area of the cylinder? Express the answer
Alex17521 [72]
Answer: D) 176 pi cm^2
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4 years ago
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
Lynna [10]
Part A:  Coefficient:  either 7.50 or 0.20
Part B:

7.50 (25) + 0.20 (300) + 40
187.50 + 60 + 40 = $287.50

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3 years ago
Long rationalise surds questions <br>pls help​
Katena32 [7]

Answer:

Noah mistakenly added 25 and 7 in denominator instead of subtracting in the third step.

Step-by-step explanation:

Noah had to rationalize the denominator of \frac{32}{5-\sqrt{7}}

According to him,

\frac{32}{5-\sqrt{7} = \frac{32(5+\sqrt{7}{(5-\sqrt{7})(5+\sqrt{7}

Solving the nominator and denominator

= \frac{160-32\sqrt{7}}{25+5\sqrt{7}-5\sqrt{7}-7}

Noah did correctly till this point.

In the next step he add 25 and 7 in the denominator, whereas, it should be subtracted.

Hence,

Noah mistakenly added 25 and 7 in denominator instead of subtracting in the third step.

3 0
3 years ago
Find the sum (3x^2+5x-8)+(5x^2-13x-5)
Radda [10]
<span>8x^2-8x-13 is the correct answer </span>
3 0
3 years ago
Read 2 more answers
Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
  • (1 - sinθ)² / cos²θ

<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
  • secθ - tanθ
<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
  • (1 - cosθ)²/sin²θ

<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
  • 1/sinθ - cosθ / sinθ =
  • cosecθ - cotθ

<u>Sum of the results:</u>

  • cosecθ + cotθ + cosecθ - cotθ =
  • 2cosecθ
4 0
3 years ago
Read 2 more answers
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