I am not a hundred percent sure but I think it is A
Hope this helps:)
Answer:
7) C) PQR ≈ TSR
8) B) 3
9) D) 102 ft
10) D) 21
11) C) 45
Step-by-step explanation:
7) C) PQR ≈ TSR
8) 2 * 6 = 12
so 4x = 12
x = 3
9)
24/20 = x/85
x = 24 * 85 / 20
x = 202 ft
10)
QT/35 = 24/40
QT/35 = 3/5
QT = 35 * 3 / 5
QT = 21
11)
ΔKLM ≈ΔXYZ
9/4 = 2.25
So
XY = 9 ---> given
YZ = 7 * 2.25 = 15.75
XZ = 9 * 2.25 = 20.25
Perimeter ΔXYZ = 9 + 15.75 + 20.25 = 45
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
Answer:
I think its A
Step-by-step explanation:
How old is her father now? That question has no answer.