The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J
The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.
However, since we are required to determine heat released when the helium gas condenses.
The heat of condensation per gram is; -21 J/g.
Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.
Approximately, -250J.
Read more on latent heat:
brainly.com/question/19863536
Answer: y = -35x + 105
Step-by-step explanation:
The graph represents a function that is between hours and miles and to determine the equation which belong to this graph, we need to find the slope first by using two points from the graph which are (0, 105) and (3, 0).
The definition of slope is
m = (y2 - y1)/(x2 - x1)
= (0-105)/3-0
= -105/3
= -35
The slope is -35 and remember that the slope is the coefficient of the variable x. Therefore, the answer is:
y = -35x + 105
You are correct. The answer is B) 5.
This is because the period here is T = 2pi/5
Multiplying 5 with this period leads to 5*(2pi/5) = 2pi; showing that 5 full cycles occupy a total horizontal width of 2pi units (more specifically stretching from 0 to 2pi).
The angels in a triangle should be 180° all
85+64+30=179<180
so we should add 1° to the first one
the angels would be 86 64 30
Answer:
The answer would be d(c(x)) = .60x - 5
Step-by-step explanation:
In order to write an equation for d(c(x)), start with the d(y) equation.
d(y) = .80y - 5
Now input the c(x) equation in for y and then solve.
d(c(x)) = .80(.75x) - 5
d(c(x)) = .60x - 5
