Percentage yield = (actual yield / theoretical
yield) x 100%<span>
The balanced equation for the reaction is,
CH₄(g) + Cl₂<span>(g) </span>→ CH₃Cl(g)
+ HCl(g)</span><span>
Since there is excess of Cl₂ gas, we can assume that all of CH₄ gas are reacted.</span><span>
Moles of CH₄(g) = mass / molar mass</span><span>
= 25.0 g / 16 g/mol
= 1.5625 mol
The stoichiometric ratio between CH₄(g) and CH₃Cl(g)
is 1 : 1</span><span>
Hence moles of CH₃Cl(g) = 1.5625 mol</span><span>
Molar mass of CH₃Cl(g) = 50.5 g/mol</span><span>
Mass of CH₃Cl(g) = number of moles x molar mass</span><span>
= 1.5625 mol x 50.5 g/mol
<span>
= 78.9 g</span>
Hence theoretical yield = 78.9 g
Actual yield = 45.0 g
Hence,
<span> Percentage yield = (45.0 g / 78.9 g) x 100% </span>
<span>
= 57.03%</span></span>
<u>We want the molar mass (gfm) of Fe and FeS.</u>
Fe = 55.8 g/mol and FeS = 87.8 g/mol (55.8 +32.0).
<u>Explanation:</u>
We want ratio between Fe:FeS 8:8. This comes from the coefficients of the equal chemical equation.
Now we set up conversion factors following the roadmap from above.
Unit we want in the numerator, unit to cancel in the denominator.
Multiply the numerators, and divide the denominators.
The outcome is 243.82 g of ferrous sulphite
By the above given formula we can find any amount of Fes produced by any amount of ferrous react with sulphite.
You can put an egg in Vinegar an egg in Olive oil
Answer:
i cant read it but its c and a
Explanation:
my thinking faces
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
