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Gelneren [198K]
3 years ago
15

WHAT ARE SOME FUN ALCHSELTER EXPERIMENTS?

Chemistry
1 answer:
Vesna [10]3 years ago
4 0
You can put an egg in Vinegar  an egg in Olive oil


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State and Explain the trend in the atomic radius down a group
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Explanation:

<h2>The number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital.</h2>
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put the following in order from LARGEST TO SMALLEST nuclueus,molecule,electron,atom,proton and a teacher
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electron, proton, nucleus, atom, molecule teacher

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3 years ago
Which of the following diagrams correctly shows the reaction pathway of a reaction that releases energy ?
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The answer is diagram A.

Hope this helped. Good luck!
3 0
3 years ago
Read 2 more answers
or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und
beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)

\Delta H^{o}_{rxn}= -5104.1kJ/mol

The expression for the entropy change for the reaction is as follows.

\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]

\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol

\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol

\Delta H^{o}_{f}(O_{2})= 0kJ/mol

Substitute the all values in the entropy change expression.

-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]

-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})

\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol

=-220.1kJ/mol

Therefore, The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

4 0
3 years ago
How many ml of co2 would be produced at 745 torr and 28°C
Marizza181 [45]

Answer:

Se aplica la leyes d ellos gases ideales para esto se convierten las unidades de Presión en atmósferas y Temperatura a Kelvin y si no se tiene el volumen el volumen equivale a 22.4Litros

Explanation:

3 0
3 years ago
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