The delta H of -484 kJ is the heat given off when 2 moles of H2 react with 1 mole of O2 to make 2 moles of H2O. You don't have anywhere near that much reactants, only 1/4 as much
<span>actual delta H = 0.34 moles H2 x (-484 kJ / 2 moles H2) = 823 kJ </span>
<span>delta E = delta H - PdeltaV = 823 kJ - 0.41 kJ = 822 kJ</span>
<em>ANSWER - 6 MOLES OF </em><em>IRON</em>
Fe2O3(s) + 3H2(g) → 2Fe(s) + 3H2O(1)
One moles of Fe2O3 forming 2 moles of Fe
3 moles of Fe2O3 will form 2×3 = 6 moles of iron
Answer:
Explanation:
Hello!
In this case, since the molarity of a solution is computed by dividing the moles of solute by the volume of solution in liters, we first need to compute the moles of solute knowing that the molar mass of calcium hydroxide is 74.1 g/mol as follows:
Next, since the 100-mL solution is also expressed in liters by 0.100 L, we directly compute the molarity as shown below:
Which is expressed in molar units that are mol/L.
Best regards!
Hello, this question is incomplete. The complete question would be:
"Write the balanced chemical equation for the following reaction.
Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water"
Answer:
Fe2O3 + 3 H2 = 2 Fe + 3 H2O
Explanation:
In a chemical reaction, the structure of atoms as chemical elements is unchanged. Atoms in one element do not become atoms in another element. There is also no loss or creation of new atoms. The number of atoms of the reagents must be equal to the number of atoms of the products. When this happens, we say that the chemical equation is balanced.
For this reason, we can state that the balanced chemical reaction where solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water would be:
<em>Fe2O3 + 3 H2 = 2 Fe + 3 H2O
</em>
100.0ml*0.400m =xml *2.00m
x=100.0*0.400/2.00= 20 ml 2.0 m CaCl2
you need to take 20 ml 2.0 m CaCl2 and dilute it with water up to 100.0 ml
