Answer:
<u>∗ = 0.4x³</u>
Step-by-step explanation:
(15y + ∗)² = 225y²+12x³y+0.16x⁶
<u>Note:</u>
225y² = 15y * 15y = (15y)²
12x³y = 2 * 15y * 0.4x³
0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²
So, by factoring the right hand side:
225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²
By comparing the left hand side with (15y + 0.4x³)²
<u>So, ∗ should be replaced with the monomial 0.4x³</u>
Use a ruler. I can't see the picture.
For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.
for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04
for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92
for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582
Answer:
18 small dogs
Step-by-step explanation:
Given the ratio of small dogs to all dogs was 3:7
Total dogs that are there = 42 dogs
Number of small dogs there = ratio of small/ratio of all dogs * Total dogs
Number of small dogs there = 3/7 * 42
Number of small dogs there = 3 * 6
Number of small dogs there = 18
Hence there are 18 small dogs there
The answer will be Negative
