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VladimirAG [237]
3 years ago
11

Suppose it is 40° inside your refrigerator and 340° inside your oven when the power goes out. The refrigerator temperature start

s rising at the rate of 5° per hour. The oven temperature starts dropping at the rate of 45° per hour.
Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

<em>The temperature of both appliances is 70° after 6 hours.</em>

<em>At 6 hours, both temperatures will be equal</em>

Step-by-step explanation:

<u>Equations</u>

Let's call

T1 = Temperature inside of the refrigerator

T2 = Temperature inside of the oven.

x  =  Time in hours elapsed since the power goes out.

We know the temperature of the refrigerator rises at 5° per hour. Thus the function that models its temperature is:

T1 = 40 + 5x

We are also given the oven temperature drops by 45° per hour, thus:

T2 = 340 - 45x

a) Find the value of x for both temperatures to be the same.

We equal T1 and T2:

40 + 5x = 340 - 45x

Adding 45x

40 + 5x + 45x = 340

Subtracting 40:

5x + 45x = 340 - 40

Operating:

50x = 300

x = 300/50

x = 6

At 6 hours, both temperatures will be equal

b)

The common temperature can be found by substituting x in any function:

T1 = 40 + 5x = 40 + 5(6) = 40 + 30 = 70

T2 = 340 - 45x = 340 - 45(6) = 70

The temperature of both appliances is 70° after 6 hours.

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Step-by-step explanation:

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4x+4x=18+50

8x=68

x=8.5

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Consider a company that selects employees for random drug tests. The company uses a computer to randomly select employee numbers
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Last week, Mrs. Thomas, the AP Statistics teacher at Green Valley High School, gave her students an assessment on material they
blondinia [14]

Answer:

0.88=\frac{X-83.54}{11.21}

And if we solve for th value of X we got:

X=83.54 + 0.88*11.21=93.405

So then the score for Andrew is 93.405.

We need to take in count that the first quarter accumulates 0.25 of the area on the left, the second quarter 0.5, the third 0.75 and the fourth 1.0 of the area on the left. Based on the value obtained for the probability of 0.811 we see that we are on the last quarter of the distribution or the fourth quarter.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(83.54,11.21)  

Where \mu=83.54 and \sigma=11.21

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we use the formula we got:

0.88=\frac{X-83.54}{11.21}

And if we solve for th value of X we got:

X=83.54 + 0.88*11.21=93.405

So then the score for Andrew is 93.405.

In order to find on which quarter is the score we just need to find this probability:

P(Z

We need to take in count that the first quarter accumulates 0.25 of the area on the left, the second quarter 0.5, the third 0.75 and the fourth 1.0 of the area on the left. Based on the value obtained for the probability of 0.811 we see that we are on the last quarter of the distribution or the fourth quarter.

7 0
4 years ago
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