With the b2+b- 12 your gonna want to do this
b2+b-12
b2+4b-3b-12
which is the sum product
after doing that you wanna common the factors from the two pairs. Which is b2+4b-3b-12 then you do you parentheses around b(b+4)-3(b+4) just like that after you do that then you rewrite it in factored form b(b+4)-3(b+4) you then want to rewrite it to this (b-3)(b+4) after that your solution will be (b-3)(b+4) for the first one.
Answer is unlikely.
Hope it helps!
Answer:
Rohan-6
amit-6
sohan-9
Step-by-step explanation:
12/2=6 rohan And amit
amit=6 so solan has to take 9
10
Answer:
Part A: 3x²(x⁸ - 16)
Part B: 3x²(x² - 2)(x² + 2) (x² - 2x + 2)(x² + 2x + 2)
Step-by-step explanation:
Part A. Factor out the greatest common factor
3x¹⁰ - 48 x²
= 3x²(x⁸ - 16)
Part B. Factor the expression completely
(i) Factor the difference of squares
x⁸ - 16
= (x⁴ - 4)(x⁴ + 4)
= (x² - 2)(x² + 2)(x⁴ + 4)
3x¹⁰ - 48 x² = 3x²(x² - 2)(x² + 2)(x⁴ + 4)
(ii) Factor the sum of squares
Use the Sophie Germain Identity to factor x⁴ + 4.
x⁴ + 4
= (x²)² + 2² (Still a sum of squares)
= (x² + 2)² - 4x² (Factor this as a difference of squares)
= (x² + 2 - 2x)(x² + 2 + 2x)
3x¹⁰ - 48 x² = 3x² (x² - 2)(x² + 2) (x² - 2x + 2)(x² + 2x + 2)
Answer:
105
Step-by-step explanation:
