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MakcuM [25]
3 years ago
12

Please help me I will make you the brainiest

Mathematics
2 answers:
Anna35 [415]3 years ago
5 0
Answer:...


Explanation:
Sedaia [141]3 years ago
4 0
Em that’s abit hard
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Someone help lolz..​
Mkey [24]
The answer is y =-4 !
6 0
3 years ago
Please help me with this!!! I will mark brainliest!!
wolverine [178]

Hello from MrBillDoesMath!

Answer:

-9 sqrt(5)


Discussion:

-2 sqrt(20) -  sqrt(125) =

-2 *2 sqrt(5) - sqrt(125)=                                as 20 = 4* 5

-4sqrt(5)- 5 sqrt(5)  =                                      as 125 = 25 *5

(-4 -5) sqrt(5) =

-9 sqrt(5)


Thank you,

MrB

8 0
3 years ago
Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

  • Derivatives
  • Derivative Notation
  • The derivative of a constant is equal to 0
  • Derivative Property: \frac{d}{dx} [cf(x)] = c \cdot f'(x)
  • Trig Derivative: \frac{d}{dx} [cos(x)] = -sin(x)

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 8 - 10cos(x)

x = 0

<u>Step 2: Differentiate</u>

  1. Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
  2. Simplify Derivative:                   g'(x) = 10sin(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em>:                    g'(0) = 10sin(0)
  2. Evaluate Trig:                      g'(0) = 10(0)
  3. Multiply:                               g'(0) = 0
3 0
3 years ago
Which postulate or theorem proves that these two triangles are congruent?
Alla [95]

AAS congruence theorem.


We know that <H is congruent to <F and <GJH is congruent to <JGF.

We also know that JG is congruent to JG, which gives us a side and two angles, so AAS would prove them congruent.

4 0
3 years ago
Read 2 more answers
Kofi estimated that he would run a total of 10 km in 1 h. In 1 h, he actually ran 46 times around a track 0.25 km long, going a
strojnjashka [21]
The equation to find percent error is

\frac{actual-theoretical}{theoretical}*100

where actual is the value that actually came out (in this case, 11.5 km) and theoretical is the value that was supposed to come out (in this case, 10 km).  Just plug in the numbers and simplify.

\frac{actual-theoretical}{theoretical}*100\\\\\frac{11.5-10}{10}*100=\frac{1.5}{10}*100=15\%\ error

So, the true answer would be 15%.  Apparently, the question you're asking takes 11.5 as the theoretical and the 10 as the actual (which I personally disagree with)

If you plugged in the numbers that way, the answer comes out to 13.04%.  So, the correct answer for your answer choices is c. 13%
3 0
3 years ago
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