Answer:
(1,2)
Step-by-step explanation:
4×1=4
3×2=6
then add 4+6 to get 10
then you do the same for the bottom so
5×1=5
4×2=8
5+8=13
Answer:
![NK = 15](https://tex.z-dn.net/?f=NK%20%3D%2015)
![JL = 26](https://tex.z-dn.net/?f=JL%20%3D%2026)
![KL = 19.85](https://tex.z-dn.net/?f=KL%20%3D%2019.85)
![\angle JKM =49](https://tex.z-dn.net/?f=%5Cangle%20JKM%20%3D49)
![\angle JML =41](https://tex.z-dn.net/?f=%5Cangle%20JML%20%3D41)
![\angle MLK = 90](https://tex.z-dn.net/?f=%5Cangle%20MLK%20%3D%2090)
![\angle MNL =90](https://tex.z-dn.net/?f=%5Cangle%20MNL%20%3D90)
![\angle KJL =41](https://tex.z-dn.net/?f=%5Cangle%20KJL%20%3D41)
Step-by-step explanation:
Given
![MK = 30](https://tex.z-dn.net/?f=MK%20%3D%2030)
![NL = 13](https://tex.z-dn.net/?f=NL%20%3D%2013)
![\angle MKL = 41](https://tex.z-dn.net/?f=%5Cangle%20MKL%20%3D%2041)
Solving (a): NK
MK is a diagonal and NK is half of the diagonal. So:
![NK = \frac{1}{2} * MK](https://tex.z-dn.net/?f=NK%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20MK)
![NK = \frac{1}{2} * 30](https://tex.z-dn.net/?f=NK%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%2030)
![NK = 15](https://tex.z-dn.net/?f=NK%20%3D%2015)
Solving (b): JL
JL is a diagonal, and it is twice of NL.
![JL = 2 * NL](https://tex.z-dn.net/?f=JL%20%3D%202%20%2A%20NL)
![JL = 2 * 13](https://tex.z-dn.net/?f=JL%20%3D%202%20%2A%2013)
![JL = 26](https://tex.z-dn.net/?f=JL%20%3D%2026)
Solving (c): KL
To solve for KL, we consider triangle KNL where:
![\angle KNL = 90](https://tex.z-dn.net/?f=%5Cangle%20KNL%20%3D%2090)
and
![KL^2 = NL^2 + NK^2](https://tex.z-dn.net/?f=KL%5E2%20%3D%20NL%5E2%20%2B%20NK%5E2)
![KL^2 = 13^2 + 15^2](https://tex.z-dn.net/?f=KL%5E2%20%3D%2013%5E2%20%2B%2015%5E2)
![KL^2 = 394](https://tex.z-dn.net/?f=KL%5E2%20%3D%20394)
![KL = \sqrt{394](https://tex.z-dn.net/?f=KL%20%3D%20%5Csqrt%7B394)
![KL = 19.85](https://tex.z-dn.net/?f=KL%20%3D%2019.85)
Solving (d - h):
To do this, we consider triangle JKN
-- diagonals bisect one another at right angle
Alternate interior angles are equal. So:
![\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41](https://tex.z-dn.net/?f=%5Cangle%20MKL%20%3D%20%5Cangle%20KMJ%20%3D%20%5Cangle%20KJL%20%3D%20%5Cangle%20JLM%20%3D%2041)
Similarly:
![\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41](https://tex.z-dn.net/?f=%5Cangle%20MKJ%20%3D%20%5Cangle%20KML%20%3D%20%5Cangle%20MJL%20%3D%20%5Cangle%20JLK%20%3D%2090%20-%2041)
![\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49](https://tex.z-dn.net/?f=%5Cangle%20MKJ%20%3D%20%5Cangle%20KML%20%3D%20%5Cangle%20MJL%20%3D%20%5Cangle%20JLK%20%3D%2049)
So:
![\angle JKM =49](https://tex.z-dn.net/?f=%5Cangle%20JKM%20%3D49)
![\angle JML =41](https://tex.z-dn.net/?f=%5Cangle%20JML%20%3D41)
![\angle MLK = \angle MLJ + \angle JLK](https://tex.z-dn.net/?f=%5Cangle%20MLK%20%3D%20%5Cangle%20MLJ%20%2B%20%5Cangle%20JLK)
![\angle MLK = 49 + 41](https://tex.z-dn.net/?f=%5Cangle%20MLK%20%3D%2049%20%2B%2041)
![\angle MLK = 90](https://tex.z-dn.net/?f=%5Cangle%20MLK%20%3D%2090)
![\angle MNL =90](https://tex.z-dn.net/?f=%5Cangle%20MNL%20%3D90)
![\angle KJL =41](https://tex.z-dn.net/?f=%5Cangle%20KJL%20%3D41)
Good night,
<span>Irrational numbers
are those that can't be expressed as a fraction:
12.89 can be expressed as: </span>
![\frac{1289}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1289%7D%7B100%7D%20)
![\frac{12}{144}= \frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7B144%7D%3D%20%5Cfrac%7B1%7D%7B12%7D%20%20)
<span>The above numbers
can be expressed as a fraction, then the logical answer is: </span>
![\sqrt{12}](https://tex.z-dn.net/?f=%20%5Csqrt%7B12%7D%20)
But we will check the answer:
![\sqrt{12}= \sqrt{2^{2}*3 } =2* \sqrt{3} =3.4641016...](https://tex.z-dn.net/?f=%20%5Csqrt%7B12%7D%3D%20%5Csqrt%7B2%5E%7B2%7D%2A3%20%7D%20%20%3D2%2A%20%5Csqrt%7B3%7D%20%3D3.4641016...)
As you can see we can't express that number as a fraction, so that is te correct answer.
Answer: 64.8 mph
Step-by-step explanation:
Given
Arriving time is 6 hours
return time is 4 hours
The average speed of returning 81 mph
Distance traveled while returning
![\Rightarrow d=81\times 4=324\ miles](https://tex.z-dn.net/?f=%5CRightarrow%20d%3D81%5Ctimes%204%3D324%5C%20miles)
the average speed of the entire trip is
![\Rightarrow v_{avg}=\dfrac{2\times 324}{6+4}=\dfrac{648}{10}=64.8\ mph](https://tex.z-dn.net/?f=%5CRightarrow%20v_%7Bavg%7D%3D%5Cdfrac%7B2%5Ctimes%20324%7D%7B6%2B4%7D%3D%5Cdfrac%7B648%7D%7B10%7D%3D64.8%5C%20mph)
Answer: z=0
Step-by-step explanation:
W=zr-2zt^3
Move all terms containing z to the left, all other terms to the right.
dd '-1rz' to each side of the equation.
-1rz+z=rz+-1rz+-2t^3z
Combine like terms: rz + -1rz = 0
-1rz+z=0+(-2t^3z)
-1rz+z=-2t^3z
Add 2t^3z to each side
-1rz+2t^3z+z=-2t^3z+2t^3z
Combine the like terms 2t^3z+2t^3z=0
-1rz+2t^3z+z=0
Factor out the Greatest Common Factor (GCF), 'z'.
z(-1r+2t^3+1)=0
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤