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vampirchik [111]
3 years ago
14

What is the distance between the two points shown on the coordinate plane below?

Mathematics
2 answers:
lilavasa [31]3 years ago
4 0

Answer: 16

Step-by-step explanation:

Sedaia [141]3 years ago
4 0

Answer:

distance =  \sqrt{ {(8 - ( - 8))}^{2} +  {( - 6 - ( - 6))}^{2}  }  \\  =   \sqrt{256}  \\  = 16 \: units

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A diameter of a circle has enpoints (-2, 10) and (6, -4) in the standard (x, y) coordinate plane. What is the center of the circ
wlad13 [49]

Answer:

The center of the circle is C(x,y) = (2, 3).

Step-by-step explanation:

The center of the circle is the midpoint of the segment between the endpoints. We can determine the location of the center by this vectorial expression:

C(x,y) = \frac{1}{2}\cdot R_{1}(x,y)+ \frac{1}{2}\cdot R_{2}(x,y) (1)

Where:

C(x,y) - Center.

R_{1} (x,y), R_{2} (x,y) - Location of the endpoints.

If we know that R_{1} (x,y) = (-2,10) and R_{2} (x,y) = (6,-4), then the location of the center of the circle is:

C(x,y) = \frac{1}{2}\cdot (-2,10)+\frac{1}{2}\cdot (6,-4)

C(x,y) = (-1, 5) + (3, -2)

C(x,y) = (2, 3)

The center of the circle is C(x,y) = (2, 3).

8 0
3 years ago
What is the inverse of the following conditional statement?
anygoal [31]

"If we are the state champions then we won the game" or C is your answer

6 0
3 years ago
Write an equation in standard form if the line that passes through (7,-3) and had a slope if 4​
zvonat [6]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

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\bf (\stackrel{x_1}{7}~,~\stackrel{y_1}{-3})~\hspace{10em} \stackrel{slope}{m}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{4}(x-\stackrel{x_1}{7})\implies y+3=4x-28 \\\\\\ y=4x-31\implies -4x+y=-31\implies 4x-y=31

8 0
3 years ago
What is the solution set of the system of inequalities 5x<8+4y and 2y≤6?
Nitella [24]

Answer:

<h2>See the explanation and the image.</h2>

Step-by-step explanation:

The inequality 2y \leq 6 means y \leq 3.

y = 0, satisfies the above inequality, so the arrows will be towards the x axis.

Now, we need to draw 5x < 8 + 4y.

First, lets draw the equation of 5x = 8 + 4y.

y = 1 gives x = 2.4 & y = 0 gives x = 1.6.

Hence, the above equation passes through (2.4, 1) and (1.6, 0).

The point (0, 0) satisfies the inequality 5x < 8 + 4y. Hence, the arrows will be towards the origin.

The solution will be the area of APQ except any point on PQ, as PQ is nothing but the line 5x = 8 + 4y.

8 0
3 years ago
Ok help me plsssssssss
Nady [450]

Answer:

the answer is a)

Step-by-step explanation:

sorry i don't what to explain here

4 0
3 years ago
Read 2 more answers
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