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strojnjashka [21]
3 years ago
13

:BfJBFLbobafofbudbnmb ggjpbpgbpgsbgubpbgbnopgnpgpngnp ya know

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

jdasoiagkjevlaagehvdlnkaaaaaaajajeghand

Step-by-step explanation:

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If \\(z_1=3+2i\\) and \\(z_2=4+3i\\) and are complex numbers, find \\(z_1z_2\\)
Mice21 [21]

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df

Step-by-step explanation:

ff

3 0
3 years ago
A box contains x apples.<br> 5 are green and the rest are red.<br> Write an expression for P(red).
zvonat [6]

Answer:

25

Step-by-step explanation:

a box contians× means 5×5=25

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2 years ago
Solve for x:
Anna71 [15]

Answer:

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4 0
3 years ago
Read 2 more answers
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
marys age is 2 upon 3 that of peters age. two years ago marys age was 1 upon 2 of whats peters age will be in 5years time. how o
Nitella [24]

Answer:

the Peter age be 27

Step-by-step explanation:

Let assume peter be

And, then mary is 2p ÷ 3

So

The equation would be  

2p ÷ 3  - 2 = 1 ÷ 2 (p + 5)

4p - 12 = 3p + 15

p = 27

So Peter age be 27

And, the mary age is

= 2 (27) ÷ 3

= 18

Hence, the Peter age be 27

4 0
2 years ago
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