∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
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If the discriminant, b² - 4ac is<u> positive</u>
<h3>How to complete the statement?</h3>
From the question, we have the following equation of discriminant
The discriminant (d) is calculated as
d = b² - 4ac
The solutions of a quadratic equation are dependent on the following conditions
- If d = 0, the quadratic equation has 1 real solution
- If d < 0, the quadratic equation has imaginary solutions
- If d > 0, the quadratic equation has 2 different real solutions
This means that "d > 0, the quadratic equation has 2 different real solutions" implies that the discriminant is positive
Hence, the complete statement is (b) positive
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Answer:
need help too
Step-by-step explanation:
I tried I hope this helps in any kind of way
Answer:
not rounded is 44.2, rouned to the nearest tenth is 40
Step-by-step explanation:
