Answer:

Step-by-step explanation:
Sonya drops a marble while standing on a deck
feet above the ground.
The marble falls
feet from Sonya's hand to the deck, and then rolls and falls to the ground.
So, the ball falls
feet from Sonya's hand to the deck and
from the deck to the ground, in total

3, 4, 1, 3, 7, 6 3, 4, 1, 3, 7, 6 Find the median of the given data.
Reil [10]
Answer:
the median is 4
Step-by-step explanation:
the median is the number in the middle and once you put all the numbers in order and slowly cross out the numbers 1 at a time on both sides you get 4
Answer:
Your solution is (-10/7, 92/7)
Step-by-step explanation:
12x + y = -4
y = 2x + 16
To use substitution, we want to plug one variable's equation into the other equation.
We can see that y is already solved for us. Plug y into the first equation.
12x + y = -4
12x + (2x + 16) = -4
Combine like terms.
14x + 16 = -4
Subtract 16 from both sides.
14x = -20
Divide both sides by 14.
x = -20/14
x = -10/7
Now that we know x, we will plug it into one of the other equations.
y = 2x + 16
y = 2(-10/7) + 16
Multiply.
y = -20/7 + 16
Add.
y = -20/7 + 112/7
y = 92/7
Your solution is (-10/7, 92/7)
Hope this helps!
Well what i did was subtract 10 from 15 it get 5 for one side length and the other would be 24-16= 8. the scale factor would be +5 and + 8.
Answer: 48 tickets
Step-by-step explanation:
Since the expression that gives the number of tickets a player wins if he shoots the ball in the hoop t times is expressed as 3t.
Therefore, the number of tickets that a player wins if he shoots the ball in the hoop 16 times will be:
= 3t
where,
t = 16
Therefore, 3t = 3 × 16 = 48
The player wins 48 tickets.