Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
X=4, -2
Step-by-step explanation:
Check attachment
Answer:
<u>Challenge #1:</u>
<u>Different examples:</u>
2x+1=3x+2
4x+3=5x+4
3x+2=4x+3
<u>Challenge #2:</u>
<u>Different examples:</u>
2x+0=4x+1
3x+1=2x+5
6x+5=8x+6
- The domain of this relationship can be defined as,
0 ≤ x ≤ 60
- The range of this relationship can be defined as,
0 ≤ y ≤ 40
Definition of Domain and Range
The set of all the possible input values for which the provided function is defined is termed as the domain of that function.
The set of all the possible values that a given function can generate as an output is termed as the range of that function.
Forming the Relation
It is given that,
- Jackson wants to purchase 2 shirts and 3 pairs of pants with his gift card
- x represents the cost of the shirts and y represents the cost of the pants
- The limit of the gift card = $120
Thus, the relation formed is given by,

Domain and Range of the Given Relation
We have,

⇒ 
⇒ 
Thus, the domain is given by,
⇒ 
Similarly,

⇒ 
Thus, the range is given by,
⇒ 
Learn more about domain and range here:
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The area of a triangle is

. solving for h (height) we get: