Evaluate the expression3+(a+4)(8-b) when a = 5 and b = 6
1 answer:
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Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
To solve the inequality, you need to isolate/get the variable "p" by itself in the inequality:
5p + 26 < 72 Subtract 26 on both sides
5p + 26 - 26 < 72 - 26
5p < 46 Divide 5 on both sides to get "p" by itself
p < 9.2 Your answer is A
Answer: OPTION A
Step-by-step explanation:
The equation of the line in slope-intercept form is:
Where m is the slope and b the y-intercept.
Solve for y from each equation:
As you can see the slope and the y-intercept of each equation are equal, this means that both are the exact same line. Therefore, you can conclude that the system has infinitely many solutions.