B and C by SSA (pls mark as brainliest)
Answer:
11/6
Step-by-step explanation:
16/3 - 7/2 = 16/3 x 2/2 - 7/2 x 3/3 = 32/6 - 21/6 = 32-21/6 = 11/6
Answer:
C
Step-by-step explanation:
We want to determine the vertex of the quadratic equation:
Recall that the vertex is given by the formulas:
In this case, <em>a</em> = -1, <em>b</em> = 2, and <em>c</em> = 1.
Determine the <em>x-</em>coordinate of the vertex:
To determine the <em>y-</em>coordinate, evaluate the function at <em>x</em> = 1:
In conclusion, the vertex of the quadratic equation is (1, 2).
Hence, our answer is C.
Answer:
When we have something like:
![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
It is called the n-th root of x.
Where x is called the radicand, and n is called the index.
Then the term:
![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
is called the fourth root of 16.
And in this case, we can see that the index is 4, and the radicand is 16.
At the end, we have the question: what is the 4th root of 16?
this is:
![\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%20%5Csqrt%5B4%5D%7B4%2A4%7D%20%20%3D%20%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%20%3D%202)
The 4th root of 16 is equal to 2.
Well I don't know !
Let's take a look and see:
The idea is that there could be more than one way
for a roll of the dice to land with the same number.
-- If the sum is from 1-4, you get the point.
There are 6 different ways for a roll of the dice to come up 1-4.
-- If the sum is from 5-8, Adam gets the point.
There are 20 different ways for a roll of the dice to come up 5-8.
-- If the sum is 9-12, Lana gets the point.
There are 10 different ways for a roll of the dice to come up 9-12.
-- The game is not fair to all three of you.
-- Lana has a distinct advantage over you.
-- Adam has a big advantage over Lana.
-- Adam has an even bigger advantage over you.
-- You are at a big disadvantage. (Notice that one of your
numbers ... 1 ... can never come up unless one of the dice
falls off of the table.)
_______________________________
Here's how to figure it:
Ways to roll a 2:
1 ... 1
Ways to roll a 3:
1 ... 2
2 ... 1
Ways to roll a 4:
1 ... 3
2 ... 2
3 ... 1
Ways to roll a 5:
1 ... 4
2 ... 3
3 ... 2
4 ... 1
Ways to roll a 6:
1 ... 5
2 ... 4
3 ... 3
4 ... 2
5 ... 1
Ways to roll a 7:
1 ... 6
2 ... 5
3 ... 4
4 ... 3
5 ... 2
6 ... 1
Ways to roll an 8:
2 ... 6
3 ... 5
4 ... 4
5 ... 3
6 ... 2
Ways to roll a 9:
3 ... 6
4 ... 5
5 ... 4
6 ... 3
Ways to roll a 10:
4 ... 6
5 ... 5
6 ... 4
Ways to roll 11:
5 ... 6
6 ... 5
Ways to roll 12:
6 ... 6
