A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
Answer:
O is greater than -4
Step-by-step explanation:
Answer: 
This can be written as a = (f-v)/t
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Work Shown:

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Note
is the same as 
V=(4/3)pir^3
r=5
v=(4/3)pi5^3
v=(4/3)pi125
V=(500/3)*3.14
v=523.33333333333333333333333333333
rounded to nearest whole
523 mm³