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3 years ago

Find the center of the circle that can be circumscribed about EFG with E(2,2),F(2,-2), and G(6,-2)

1 answer:

6 0

Hmmm I'd say the center of the circle will end up at the center of the triangle, namely the Centroid of the triangle circumscribed in the circle.

$\bf \textit{Centroid of a Triangle}
\begin{array}{llll}
\stackrel{E(2,2)~~F(2,-2)~~G(6,-2)}{\left(\cfrac{2+2+6}{3}\quad ,\cfrac{2-2-2}{3}\quad \right)}
\end{array}$

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Quadratic Functions: Vertex Form

Keith_Richards [23]

Answer:

(5, -9).

Step-by-step explanation:

The vertex if (h, k).

So for 6(x - 5)^2 - 9 the vertex is the point (5, -9).

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3 years ago

99 Points!

patriot [66]

Simple...

you have:

1.) Find the slope of the line using (-2,1) and (3,6)

Using $\frac{ y_{1}- y_{2} }{ x_{1} - x_{2} }$

$\frac{1-6}{-2-3} = \frac{-5}{-5}$

m=1 (slope)

2.)Tell whether the equation, 8y+3=5x+3, is a direct variation.

y= $\frac{5x}{8}$ (None)

3.)What is the slope and y-intercept of the graph of the equation y=2x+3?

Slope =2

y-intercept=3

C.

Thus, your answer.

3 0

3 years ago

What is the value of the underlined digit 24 the 2 is underlined?

zhannawk [14.2K]

Answer:

Step-by-step explanation:

ones= 1

tens= 10

Hundreds= 100

The difference between ones and tens is the 0. ones=1. tens=10

<u>2</u>4

The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place

3 0

3 years ago

One of the solutions of the system of equations shown in the graph has an x-value of –4. What is its corresponding integer y-val

jeka57 [31]

The solution is (-4, -1

7 0

3 years ago

Read 2 more answers

The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31

4 0

3 years ago