Answer:
2500 kb
Explanation:
Here, we are to calculate the bandwidth delay product
From the question, we are given that
band width = 500 Mbps
The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3
= 2500 Kbits
Id say Router is the answer based on your Question.
Router - is a device used to host a network signal which people will require the SSID(network-name) to connect to.
It is a bit confusing because the correct answer is SSID which leads me to belive Public Wi-Fi is also correct..
Answer:
I would say b but if I'm wrong take the point back
Answer:
Explanation:
The following code is written in Java and runs a thread every 45 seconds that adds the two counters together and saves them in an integer variable called register. Then prints the variable. If this code runs 5 times it automatically breaks the loop. This can be changed or removed by removing the breakLoopCounter variable.
public static void add_Counters(int counterOne, int counterTwo) {
int register = 0;
int breakLoopCounter = 0;
try {
while (true) {
register += counterOne + counterTwo;
System.out.println(register);
Thread.sleep(45000);
breakLoopCounter += 1;
if (breakLoopCounter == 5) {
break;
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Answer:
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