The sales for January, February, and March are $150,000, $180,000 and $220,000, respectively. For any particular month of sa
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Solution
S = 15 x x
Total cost, T = wL + rC = 50L + 100C
Total revenue, R = Output price (P) x Quantity = P x 15 x x
(a)
Optimization problem will be:
Max R = P x 15 x x
Subject to T = 50L + 100C
(b) When S = 50,000
Cost is minimized when (MPL / MPC) = w / r
MPL = R /
L = P x 15 x 0.2 x
= P x 3 x
MPC = R /
C = P x 15 x 0.8 x
= P x 12 x
MPL / MPC = (3/12) x (C / L) = 50/100
C / 4L = 1/2
4L = 2C
2L = C
Substituting in production function,
15 x x
= S
15 x x
= 50,000
15 x x
x
= 50,000
L = 50,000 / (15 x 20.8)
L = 1,914.50
C = 2L = 3,829.00
Total cost ($) = 50 x 1,914.50 + 100 x 3,829.00 = 95,725.00 + 382,900 = 478,625.00
Note: This optimization problem can be solved without using Solver too, as shown here.