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jasenka [17]
3 years ago
15

Write an inequality to represent the graph. у -5 3 2- x -5 4 3 2 0 2 5 6 8 -2 -3 -5 (3,5) -6- (0,7) -8 -9 -10

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

3rd one I think

Step-by-step explanation:

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In a photograph, a house is 4 inches wide and 6 inches tall. The photograph is enlarged while keeping proportional dimensions, a
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New width / old width = 9/4 = 2.25

Multiply the original height by the scale:

6 x 2.25 = 13.5

Answer: 13.5 inches

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What operation should you perform first when you evaluate the expression 85+(9−25×5)÷3
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Read 2 more answers
HELP ME PLEASE IT¨s MATH
Arlecino [84]

Answer:

V=πr^2h

pi = 3.14

r = 2

r^2 = 4

h = 10

Multiply all the numbers to get the volume.

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V = 125.6 cubic inches

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3 years ago
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GarryVolchara [31]

Step-by-step explanation:

please mark me as brainlest

4 0
2 years ago
Consider the force field and circle defined below.
grin007 [14]

By Green's theorem,

\displaystyle\int_{x^2+y^2=9}\vec F(x,y)\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^2)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=\iint_Dy\,\mathrm dx\,\mathrm dy

where C is the circle x^2+y^2=9 and D is the interior of C, or the disk x^2+y^2\le1.

Convert to polar coordinates, taking

\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta

Then the work done by \vec F on the particle is

\displaystyle\iint_Dy\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^3(r\sin\theta)r\,\mathrm dr\,\mathrm d\theta=\left(\int_0^{2\pi}\sin\theta\,\mathrm d\theta\right)\left(\int_0^3r^2\,\mathrm dr\right)=\boxed0

4 0
3 years ago
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