Amines can be made by the reduction of nitriles, which in turn can be made from an alkyl halide. Draw the structures of a starti
ng alkyl bromide and the intermediate nitrile that would be used in the synthesis of 3-methylbutylamine (also known as isoamylamine). Do not show free ions.
1 answer:
Answer:
The structrues are shown below.
Explanation:
The compound 3-methylbutylamine has 4 carbons at the principal chain with simple bonds between then (butyl), has a ramification with a CH₃ group at the carbon 3 (methyl), and at the carbon 1 has the amine group NH₂, as shown below.
A nitrile is a compound that has the bond C≡N at the structure, so the nitrile that originates the amide must be the 3-methylbutylnitrile, with the structure shown below (only eliminated the hydrogens from N and carbon, and then added the triple bond).
The alkyl bromide must react with a cyanide salt, which will replace the Br for CN in the compound, so we must replaced the CN for Br in the structure shown below, having the Bromo-2-methylpropane.
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Explanation:
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In this case, since the dilution processes are characterized by the decrease of the original stock solution by holding the moles constant and therefore modify the volume, for the described dilution we can write:
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Answer:- Third choice is correct, 17.6 moles
Solution:- The given balanced equation is:
We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.
From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.
It is a simple mole to mole conversion problem. We solve it using dimensional set up as:
= 17.6 mol KOH
So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.