The the precipitate : Al(OH)₃(s)
The spectator ions : 3Cl⁻ and 3K⁺
<h3>Further explanation</h3>
Reaction
AlCl₃ + 3KOH → Al(OH)₃ + 3KCl
From solubility rules :
Compounds of OH− are insoluble except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺ , Sr²⁺, and Ba²⁺
Compounds of Cl−, Br−, I− are soluble except Ag⁺, Hg₂²⁺, Pb²⁺
So the the precipitate : Al(OH)₃(s)
net ionic reaction
AlCl₃ + 3KOH → Al(OH)₃ + 3KCl
Al³⁻+3Cl⁻+3K⁺+3OH⁻⇒Al(OH)₃(s)+3K⁺+3Cl⁻
Remove the spectator : 3Cl⁻ and 3K⁺
Al³⁻(aq)+3OH⁻(aq)⇒Al(OH)₃(s)
