1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksenya-84 [330]
4 years ago
6

Arrange the following set of atoms in order of decreasing atomic size: Sn, I, Sr

Chemistry
1 answer:
vampirchik [111]4 years ago
3 0
Atomic size
Sr>Sn>I

A)
B)
You might be interested in
In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.
tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ ×\frac{1mol}{212,27 g} = 0,0655 moles of K₃PO₄

The molarity of the solution is:

\frac{0,0655 moles}{0,25L} = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

\frac{0,1965 moles}{0,25L} = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

I hope it helps!

4 0
3 years ago
A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life
mixas84 [53]
T is amount after time t 
<span>Ao is initial amount </span>
<span>t is time </span>
<span>HL is half life </span>

<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>

<span>( log At - log Ao) / log (1/2) = t / HL </span>
<span>log (At/Ao) / log (1/2) = t / HL </span>

<span>HL = t / [( log (At / Ao)) / log (1/2) ] </span>

<span>HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] </span>

<span>HL = 14.4 s / 2 = 7.2 seconds </span>
8 0
3 years ago
What is the purpose of finding oxidation states in the half-reaction method for balancing equations?
vazorg [7]

Answer:

B. To Identify the half reactions for the equation

4 0
3 years ago
3. Classify the following plants along with two main characteristics: al Cycus b) Bamboo c) Lemna d) Paddy a) Sugarcane f) Pinus
madreJ [45]

Answer:

A. cycas

1. it is thick and scaly

2. it grow relatively slowly and have a large, terminal rosette of leaves.

B. bamboo

1. it is very durable

2. it is both flexible and elastic

C. lemna

1. it grows as simple free-floating thalli on or just beneath the water surface

2. it are small, not exceeding 5 mm in length

D. paddy

1. it is variety purity

2. it degree of purity

E. sugarcane

1. it is bear long sword-shaped leaves

2. it's stalks are composed of many segments, and in each joint there is a bud

4 0
2 years ago
HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make
vazorg [7]

<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.

<u>Explanation:</u>

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

\Delta G=\Delta H-T\Delta S

Where,

\Delta G = change in Gibb's free energy

\Delta H = change in enthalpy

T = temperature

\Delta S = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and Delta S is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the \Delta H is also negative.

For a reaction to be spontaneous, \Delta G must be negative.

-ve=-ve-[T(-ve)]\\\\-ve=-ve+T

From above equations, it is visible that \Delta G will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0
3 years ago
Other questions:
  • Which actions represent endothermic reactions? Check all that apply. an instant ice pack becoming cold, splitting a gas molecule
    8·2 answers
  • The substances sodium (Na), oxygen (O2), and sodium oxide (Na20) participate in this chemical reaction
    7·1 answer
  • Which of the five most abundant elements are metals?
    9·1 answer
  • What are the different acid bases
    15·1 answer
  • Y’all pls help me with this I’m literally so done
    10·1 answer
  • 8. Water behind a dam, a moving car, and electricity moving in a circuit all are examples of
    11·1 answer
  • Scientists who are investigating what has happened over the years to the people who were exposed to radiation during the 1986 Ch
    13·1 answer
  • Pls someone help me out
    9·1 answer
  • Which of the following is an example of a chemical change?
    10·1 answer
  • Explain a mixture of molecules
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!