Answer:
The table a not represent a proportional relationship between the two quantities
The table b represent a proportional relationship between the two quantities
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or 
<u><em>Verify each table</em></u>
<em>Table a</em>
Let
A ----> the independent variable or input value
B ----> the dependent variable or output value
the value of k will be

For A=35, B=92 ---> 
For A=23, B=80 ---> 
the values of k are different
therefore
There is no proportional relationship between the two quantities
<em>Table b</em>
Let
C ----> the independent variable or input value
D ----> the dependent variable or output value
the value of k will be

For C=20, D=8 ---> 
For C=12.5, D=5 ---> 
the values of k are equal
therefore
There is a proportional relationship between the two quantities
The linear equation is equal to

According to my calculations it should be 52 pages
$240
Step-by-step explanation:
300×0.80 OR 300-(300×0.20)
It appears that no graph photos have been uploaded, however, I have pasted the graph for the equation Y= -4 sqrt x.
https://www.symbolab.com/solver/step-by-step/y%3D-4%5Csqrt%7Bx%7D
The speed of both the cars are 80km/h and 60km/h
<u>Step-by-step explanation:</u>
Let the speed of one car be 'a' and the speed of other car be 'b'.
The total distance (d) = 480km
It is given that the speed of one car is 20km/h faster than the other.
We can write,
a = b+20
The slower car takes 2 hrs more to reach the suburb than the other car.
Let the time taken by the fastest car be t
Speed = distance/time
So,
a = 480/ t
b = 480/(t+2)
We got the values of a and b.
a = b+20
480/t = (480/(t+2)) + 20
Taking LCM on the right side.
480/t = (480 + 20t + 40) / (t+2)
480(t+2) = (480+20t+40) t
480t + 960 = 480t + 20t(t) + 40t
20t(t) + 40t - 960 = 0
Divide the whole equation by 20 to simplify the equation.
t(t) + 2t - 48 = 0
Solve the quadratic equation by splitting the middle terms.
t(t) + 8t - 6t - 48 = 0
t(t + 8) - 6(t + 8) = 0
(t- 6) (t+8) =0
t = 6 (or) -8
t is time and cannot be negative. So t= 6hrs
a = 480/t
a = 480/ 6 = 80
the speed of the fastest car is 80km/hr
a = b + 20
b = a - 20
b = 80 - 20
b = 60km/h