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erastova [34]
4 years ago
5

What is h > 32 in inequality

Mathematics
1 answer:
Marizza181 [45]4 years ago
8 0

Answer:

Sorry I don't know the answer

You might be interested in
What isn’t the minimum value of c=7x+8y given the constraints on x and y listed below
Luda [366]

Answer:

32 is not minimum value of C

Step-by-step explanation:

Given constraints:

2x+y\geq8

x+y\geq8

x\geq8

y\geq8

Now we draw the graph of each constraint and see the feasible region in graph. Please have a look attached graph.

We got three corner points A(0,8)  B(2,4)  and C(6,0)

Now we find the optimal solution for each value of corner points.

C(0,8)=7(0)+8(8)=64

C(2,4)=7(2)+8(4)=14+32=46

C(6,0)=7(6)+8(0)=42

Option A is correct. 32 is not minimum value of C

7 0
4 years ago
Read 2 more answers
Hey anybody plz help me ;C
jekas [21]

Answer:

her equation should be a² + 3² = 4²

Step-by-step explanation:

a² + 3² = 4²

a² + 9 = 16

a² = 7

a = \sqrt{7}

a ≈ 2.6 inches

3 0
3 years ago
The area of a rectangle is 48ft2. The length is 3 times the width. Which of the following equations can be used to solve for the
emmainna [20.7K]

Answer:

Width of rectangle = 4 ft

Step-by-step explanation:

Given:

Area of rectangle = 48 ft²

Length of rectangle = 3[Width of rectangle]

Find:

Width of rectangle

Computation:

Assume;

Width of rectangle = a

So,

Length of rectangle = 3[Width of rectangle]

Length of rectangle = 3a

Area of rectangle = l x b

48 = 3a x a

3a² = 48

a² = 16

a = 4

Width of rectangle = 4 ft

Length of rectangle = 3[Width of rectangle]

Length of rectangle = 3[4]

Length of rectangle = 12 ft

6 0
3 years ago
X²+y²+14-4y-11+0 determine the center and the radious
marishachu [46]

Answer:

The Center: (0, 2)

The Radius: 1

Step-by-step explanation:

8 0
4 years ago
Triangular a Recallyuldl
kramer

i got 28cm.... But im not sure

5 0
4 years ago
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