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Masja [62]
3 years ago
13

Find the domain for the expression: y/y-5 + 1/y+8

Mathematics
2 answers:
Jet001 [13]3 years ago
7 0

Answer:

1/y+4

Step-by-step explanation:

1-5+1/y+8

1/y+(1-5+8)

1/y+4

maria [59]3 years ago
3 0

\frac{y}{y}  - 5 +  \frac{1}{y} + 8

→(1 - 5) + \frac{1}{y}  + 8

→-4 = \frac{ - 4}{1}  =  \frac{ - 4 \: • \: y}{y}

→\frac{ - 4 \: • \: y + 1}{y}  =  \frac{1 - 4y}{y}

→\frac{(1 - 4y)}{y}   + 8

→8 =  \frac{8}{1} =  \frac{8 \: • \: y}{y}

→\frac{(1 - 4y) + 8 \: • \: y}{y}  =  \frac{4y + 1}{y}

→\frac{4y + 1}{y}

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Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

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So we replace our 1 with log₂2

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log₂ on bothside will cancel each other.

We will be left with;

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log = power of exponential

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Square bothside

(√4x)² = 4²

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8 0
3 years ago
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Answer:

C

Step-by-step explanation:

If you have a Ti-84 series calculator, press "stat" then "Edit..." and then fill in the data table values for x and y in two lists. Then press "2nd" and "mode" to quit. Now press "stat" again and right arrow over to "calc" and press down until you find "ExpReg" and set the "Xlist" and "Ylist" that you used and you will get C as the answer. Another way to do this is to manually substitute values into all 4 equations, which is boring.

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2 years ago
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umka2103 [35]

Answer:

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Step-by-step explanation:

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From the graph, the point of intersection of the graphs of the two linear equations is on the y-axis. So, the x value on the y axis is always 0. Also, the point is below the x-axis. So, the y value of the point will be negative.

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Hope this helps!
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3 years ago
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